Base | Representation |
---|---|
bin | 11101110010111011100110… |
… | …001011101001010011111010 |
3 | 122011222121200212101120112122 |
4 | 131302323212023221103322 |
5 | 114134003201341412214 |
6 | 1142412244542041242 |
7 | 36413365324410164 |
oct | 3562734613512372 |
9 | 564877625346478 |
10 | 131043314013434 |
11 | 38833180517539 |
12 | 128450a4879222 |
13 | 5817440380b74 |
14 | 245075cd99934 |
15 | 1023b0d71688e |
hex | 772ee62e94fa |
131043314013434 has 8 divisors (see below), whose sum is σ = 196565021241600. Its totient is φ = 65521640266236.
The previous prime is 131043314013433. The next prime is 131043314013463. The reversal of 131043314013434 is 434310413340131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 131043314013394 and 131043314013403.
It is not an unprimeable number, because it can be changed into a prime (131043314013433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7228967 + ... + 17729765.
It is an arithmetic number, because the mean of its divisors is an integer number (24570627655200).
Almost surely, 2131043314013434 is an apocalyptic number.
131043314013434 is a deficient number, since it is larger than the sum of its proper divisors (65521707228166).
131043314013434 is a wasteful number, since it uses less digits than its factorization.
131043314013434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16740484.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 131043314013434 its reverse (434310413340131), we get a palindrome (565353727353565).
The spelling of 131043314013434 in words is "one hundred thirty-one trillion, forty-three billion, three hundred fourteen million, thirteen thousand, four hundred thirty-four".
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