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13104331431441 = 39074815998321
BaseRepresentation
bin1011111010110001011100…
…0001010001111000010001
31201101202120101111101102220
42332230113001101320101
53204200132321301231
643512014033131253
72521520356213035
oct276542701217021
951352511441386
1013104331431441
1141a25745113a8
12157785a0b9b29
1374096b970a33
143343784321c5
1517ad18cb3896
hexbeb17051e11

13104331431441 has 8 divisors (see below), whose sum is σ = 17491705905504. Its totient is φ = 8726588955840.

The previous prime is 13104331431427. The next prime is 13104331431481. The reversal of 13104331431441 is 14413413340131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13104331431441 - 239 = 12554575617553 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13104331431481) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2407996440 + ... + 2408001881.

It is an arithmetic number, because the mean of its divisors is an integer number (2186463238188).

Almost surely, 213104331431441 is an apocalyptic number.

It is an amenable number.

13104331431441 is a deficient number, since it is larger than the sum of its proper divisors (4387374474063).

13104331431441 is an equidigital number, since it uses as much as digits as its factorization.

13104331431441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4815999231.

The product of its (nonzero) digits is 20736, while the sum is 33.

Adding to 13104331431441 its reverse (14413413340131), we get a palindrome (27517744771572).

The spelling of 13104331431441 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, four hundred thirty-one thousand, four hundred forty-one".

Divisors: 1 3 907 2721 4815998321 14447994963 4368110477147 13104331431441