Base | Representation |
---|---|
bin | 11101110010111011100111… |
… | …010000110000010111000010 |
3 | 122011222121202010111000010112 |
4 | 131302323213100300113002 |
5 | 114134003221011131432 |
6 | 1142412250430231322 |
7 | 36413365634403650 |
oct | 3562734720602702 |
9 | 564877663430115 |
10 | 131043332130242 |
11 | 3883318a770a04 |
12 | 128450aa955542 |
13 | 581744405507c |
14 | 2450761553dd0 |
15 | 1023b100e47b2 |
hex | 772ee74305c2 |
131043332130242 has 16 divisors (see below), whose sum is σ = 232392116093760. Its totient is φ = 54224827088208.
The previous prime is 131043332130223. The next prime is 131043332130247. The reversal of 131043332130242 is 242031233340131.
It is a junction number, because it is equal to n+sod(n) for n = 131043332130199 and 131043332130208.
It is not an unprimeable number, because it can be changed into a prime (131043332130247) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 161383413548 + ... + 161383414359.
It is an arithmetic number, because the mean of its divisors is an integer number (14524507255860).
Almost surely, 2131043332130242 is an apocalyptic number.
131043332130242 is a deficient number, since it is larger than the sum of its proper divisors (101348783963518).
131043332130242 is a wasteful number, since it uses less digits than its factorization.
131043332130242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 322766827945.
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 131043332130242 its reverse (242031233340131), we get a palindrome (373074565470373).
The spelling of 131043332130242 in words is "one hundred thirty-one trillion, forty-three billion, three hundred thirty-two million, one hundred thirty thousand, two hundred forty-two".
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