Base | Representation |
---|---|
bin | 11101110010111011100111… |
… | …010000110000010110101111 |
3 | 122011222121202010111000002211 |
4 | 131302323213100300112233 |
5 | 114134003221011131343 |
6 | 1142412250430231251 |
7 | 36413365634403622 |
oct | 3562734720602657 |
9 | 564877663430084 |
10 | 131043332130223 |
11 | 3883318a770997 |
12 | 128450aa955527 |
13 | 5817444055066 |
14 | 2450761553db9 |
15 | 1023b100e479d |
hex | 772ee74305af |
131043332130223 has 2 divisors, whose sum is σ = 131043332130224. Its totient is φ = 131043332130222.
The previous prime is 131043332130199. The next prime is 131043332130247. The reversal of 131043332130223 is 322031233340131.
It is a balanced prime because it is at equal distance from previous prime (131043332130199) and next prime (131043332130247).
It is a cyclic number.
It is not a de Polignac number, because 131043332130223 - 29 = 131043332129711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131043332130253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521666065111 + 65521666065112.
It is an arithmetic number, because the mean of its divisors is an integer number (65521666065112).
Almost surely, 2131043332130223 is an apocalyptic number.
131043332130223 is a deficient number, since it is larger than the sum of its proper divisors (1).
131043332130223 is an equidigital number, since it uses as much as digits as its factorization.
131043332130223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23328, while the sum is 31.
Adding to 131043332130223 its reverse (322031233340131), we get a palindrome (453074565470354).
The spelling of 131043332130223 in words is "one hundred thirty-one trillion, forty-three billion, three hundred thirty-two million, one hundred thirty thousand, two hundred twenty-three".
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