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13104342233113 is a prime number
BaseRepresentation
bin1011111010110001011110…
…1010011111000000011001
31201101202121010211011112211
42332230113222133000121
53204200143102424423
643512015100435121
72521520550061555
oct276542752370031
951352533734484
1013104342233113
1141a257a6198aa
121577861848aa1
13740970c83461
14334379a44865
1517ad19be910d
hexbeb17a9f019

13104342233113 has 2 divisors, whose sum is σ = 13104342233114. Its totient is φ = 13104342233112.

The previous prime is 13104342233063. The next prime is 13104342233123. The reversal of 13104342233113 is 31133224340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12199393374169 + 904948858944 = 3492763^2 + 951288^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104342233113 - 217 = 13104342102041 is a prime.

It is not a weakly prime, because it can be changed into another prime (13104342233123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552171116556 + 6552171116557.

It is an arithmetic number, because the mean of its divisors is an integer number (6552171116557).

Almost surely, 213104342233113 is an apocalyptic number.

It is an amenable number.

13104342233113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104342233113 is an equidigital number, since it uses as much as digits as its factorization.

13104342233113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13104342233113 its reverse (31133224340131), we get a palindrome (44237566573244).

The spelling of 13104342233113 in words is "thirteen trillion, one hundred four billion, three hundred forty-two million, two hundred thirty-three thousand, one hundred thirteen".