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13104342233131 is a prime number
BaseRepresentation
bin1011111010110001011110…
…1010011111000000101011
31201101202121010211011120111
42332230113222133000223
53204200143102430011
643512015100435151
72521520550061612
oct276542752370053
951352533734514
1013104342233131
1141a257a619916
121577861848ab7
13740970c83476
14334379a44879
1517ad19be9121
hexbeb17a9f02b

13104342233131 has 2 divisors, whose sum is σ = 13104342233132. Its totient is φ = 13104342233130.

The previous prime is 13104342233123. The next prime is 13104342233137. The reversal of 13104342233131 is 13133224340131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13104342233131 - 23 = 13104342233123 is a prime.

It is a super-2 number, since 2×131043422331312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13104342233093 and 13104342233102.

It is not a weakly prime, because it can be changed into another prime (13104342233137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552171116565 + 6552171116566.

It is an arithmetic number, because the mean of its divisors is an integer number (6552171116566).

Almost surely, 213104342233131 is an apocalyptic number.

13104342233131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104342233131 is an equidigital number, since it uses as much as digits as its factorization.

13104342233131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13104342233131 its reverse (13133224340131), we get a palindrome (26237566573262).

The spelling of 13104342233131 in words is "thirteen trillion, one hundred four billion, three hundred forty-two million, two hundred thirty-three thousand, one hundred thirty-one".