13104402510523 has 4 divisors (see below), whose sum is σ = 13118153196168. Its totient is φ = 13090651824880.

The previous prime is 13104402510439. The next prime is 13104402510533. The reversal of 13104402510523 is 32501520440131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13104402510523 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104402510533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6875341393 + ... + 6875343298.

It is an arithmetic number, because the mean of its divisors is an integer number (3279538299042).

Almost surely, 2^{13104402510523} is an apocalyptic number.

13104402510523 is a deficient number, since it is larger than the sum of its proper divisors (13750685645).

13104402510523 is an equidigital number, since it uses as much as digits as its factorization.

13104402510523 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13750685644.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 13104402510523 its reverse (32501520440131), we get a palindrome (45605922950654).

The spelling of 13104402510523 in words is "thirteen trillion, one hundred four billion, four hundred two million, five hundred ten thousand, five hundred twenty-three".