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13104403314521 = 16811779513611
BaseRepresentation
bin1011111010110001101101…
…0011011111011101011001
31201101202202101202102111012
42332230123103133131121
53204200304222031041
643512025121543305
72521522221211511
oct276543323373531
951352671672435
1013104403314521
1141a2601049202
12157787a1a4b35
1374098081b6bc
14334383bc4841
1517ad202623eb
hexbeb1b4df759

13104403314521 has 4 divisors (see below), whose sum is σ = 13105182844944. Its totient is φ = 13103623784100.

The previous prime is 13104403314491. The next prime is 13104403314529. The reversal of 13104403314521 is 12541330440131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13104403314521 - 210 = 13104403313497 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104403314529) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 389739995 + ... + 389773616.

It is an arithmetic number, because the mean of its divisors is an integer number (3276295711236).

Almost surely, 213104403314521 is an apocalyptic number.

It is an amenable number.

13104403314521 is a deficient number, since it is larger than the sum of its proper divisors (779530423).

13104403314521 is an equidigital number, since it uses as much as digits as its factorization.

13104403314521 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 779530422.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 13104403314521 its reverse (12541330440131), we get a palindrome (25645733754652).

The spelling of 13104403314521 in words is "thirteen trillion, one hundred four billion, four hundred three million, three hundred fourteen thousand, five hundred twenty-one".

Divisors: 1 16811 779513611 13104403314521