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13104404300041 = 131169843588977
BaseRepresentation
bin1011111010110001101101…
…0111010000000100001001
31201101202202110121111100221
42332230123113100010021
53204200310000100131
643512025155030041
72521522232454655
oct276543327200411
951352673544327
1013104404300041
1141a260166168a
12157787a59b321
13740980aa5152
14334383d9da65
1517ad203a9411
hexbeb1b5d0109

13104404300041 has 8 divisors (see below), whose sum is σ = 13204538085024. Its totient is φ = 13004272032960.

The previous prime is 13104404300023. The next prime is 13104404300047. The reversal of 13104404300041 is 14000340440131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13104404300041 - 27 = 13104404299913 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13104404299979 and 13104404300015.

It is not an unprimeable number, because it can be changed into a prime (13104404300047) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21954945 + ... + 22543921.

It is an arithmetic number, because the mean of its divisors is an integer number (1650567260628).

Almost surely, 213104404300041 is an apocalyptic number.

It is an amenable number.

13104404300041 is a deficient number, since it is larger than the sum of its proper divisors (100133784983).

13104404300041 is a wasteful number, since it uses less digits than its factorization.

13104404300041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 758951.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13104404300041 its reverse (14000340440131), we get a palindrome (27104744740172).

The spelling of 13104404300041 in words is "thirteen trillion, one hundred four billion, four hundred four million, three hundred thousand, forty-one".

Divisors: 1 131 169843 588977 22249433 77155987 100033620611 13104404300041