Base | Representation |
---|---|
bin | 1011111010110001101111… |
… | …0100101010111000001010 |
3 | 1201101202210000010022020121 |
4 | 2332230123310222320022 |
5 | 3204200313433341132 |
6 | 43512030032213454 |
7 | 2521522355144641 |
oct | 276543364527012 |
9 | 51352700108217 |
10 | 13104412012042 |
11 | 41a2605a4983a |
12 | 157788109a28a |
13 | 740982575470 |
14 | 33438500a358 |
15 | 17ad20dce497 |
hex | beb1bd2ae0a |
13104412012042 has 16 divisors (see below), whose sum is σ = 21192004808352. Its totient is φ = 6041521802160.
The previous prime is 13104412012007. The next prime is 13104412012187. The reversal of 13104412012042 is 24021021440131.
It is a super-2 number, since 2×131044120120422 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13104412011998 and 13104412012016.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 277824184 + ... + 277871347.
It is an arithmetic number, because the mean of its divisors is an integer number (1324500300522).
Almost surely, 213104412012042 is an apocalyptic number.
13104412012042 is a deficient number, since it is larger than the sum of its proper divisors (8087592796310).
13104412012042 is a wasteful number, since it uses less digits than its factorization.
13104412012042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 555696453.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 13104412012042 its reverse (24021021440131), we get a palindrome (37125433452173).
The spelling of 13104412012042 in words is "thirteen trillion, one hundred four billion, four hundred twelve million, twelve thousand, forty-two".
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