Base | Representation |
---|---|
bin | 11101110010111100011110… |
… | …000010111001011110010001 |
3 | 122011222201010011221211202212 |
4 | 131302330132002321132101 |
5 | 114134012111304310213 |
6 | 1142412521542121505 |
7 | 36413430464632112 |
oct | 3562743602713621 |
9 | 564881104854685 |
10 | 131044251244433 |
11 | 3883361156900a |
12 | 12845306720295 |
13 | 581755c5b1917 |
14 | 245080b648209 |
15 | 1023b65b499a8 |
hex | 772f1e0b9791 |
131044251244433 has 2 divisors, whose sum is σ = 131044251244434. Its totient is φ = 131044251244432.
The previous prime is 131044251244427. The next prime is 131044251244447. The reversal of 131044251244433 is 334442152440131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130994251153984 + 50000090449 = 11445272^2 + 223607^2 .
It is a cyclic number.
It is not a de Polignac number, because 131044251244433 - 26 = 131044251244369 is a prime.
It is a super-2 number, since 2×1310442512444332 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131044251244463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522125622216 + 65522125622217.
It is an arithmetic number, because the mean of its divisors is an integer number (65522125622217).
Almost surely, 2131044251244433 is an apocalyptic number.
It is an amenable number.
131044251244433 is a deficient number, since it is larger than the sum of its proper divisors (1).
131044251244433 is an equidigital number, since it uses as much as digits as its factorization.
131044251244433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 552960, while the sum is 41.
The spelling of 131044251244433 in words is "one hundred thirty-one trillion, forty-four billion, two hundred fifty-one million, two hundred forty-four thousand, four hundred thirty-three".
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