Base | Representation |
---|---|
bin | 10011000100011100100… |
… | …011001100011111010001 |
3 | 11122021111002121022101202 |
4 | 103010130203030133101 |
5 | 132432242131413041 |
6 | 2442002031040545 |
7 | 163451011220366 |
oct | 23043443143721 |
9 | 4567432538352 |
10 | 1310444013521 |
11 | 465835534125 |
12 | 191b81070155 |
13 | 96760a967b6 |
14 | 475d668c46d |
15 | 2414ac8ca9b |
hex | 1311c8cc7d1 |
1310444013521 has 2 divisors, whose sum is σ = 1310444013522. Its totient is φ = 1310444013520.
The previous prime is 1310444013517. The next prime is 1310444013533. The reversal of 1310444013521 is 1253104440131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 926088652225 + 384355361296 = 962335^2 + 619964^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310444013521 - 22 = 1310444013517 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310444013721) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655222006760 + 655222006761.
It is an arithmetic number, because the mean of its divisors is an integer number (655222006761).
Almost surely, 21310444013521 is an apocalyptic number.
It is an amenable number.
1310444013521 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310444013521 is an equidigital number, since it uses as much as digits as its factorization.
1310444013521 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 1310444013521 its reverse (1253104440131), we get a palindrome (2563548453652).
The spelling of 1310444013521 in words is "one trillion, three hundred ten billion, four hundred forty-four million, thirteen thousand, five hundred twenty-one".
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