13104440153041 has 4 divisors (see below), whose sum is σ = 13270319142400. Its totient is φ = 12938561163684.

The previous prime is 13104440153027. The next prime is 13104440153047. The reversal of 13104440153041 is 14035104440131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13104440153041 - 2¹¹ = 13104440150993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13104440152994 and 13104440153012.

It is not an unprimeable number, because it can be changed into a prime (13104440153047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82939494561 + ... + 82939494718.

It is an arithmetic number, because the mean of its divisors is an integer number (3317579785600).

Almost surely, 2^{13104440153041} is an apocalyptic number.

It is an amenable number.

13104440153041 is a deficient number, since it is larger than the sum of its proper divisors (165878989359).

13104440153041 is an equidigital number, since it uses as much as digits as its factorization.

13104440153041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 165878989358.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 13104440153041 its reverse (14035104440131), we get a palindrome (27139544593172).

The spelling of 13104440153041 in words is "thirteen trillion, one hundred four billion, four hundred forty million, one hundred fifty-three thousand, forty-one".