13104440312233 has 4 divisors (see below), whose sum is σ = 13104605105280. Its totient is φ = 13104275519188.

The previous prime is 13104440312219. The next prime is 13104440312287. The reversal of 13104440312233 is 33221304440131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13104440312233 - 2¹³ = 13104440304041 is a prime.

It is a super-3 number, since 3×13104440312233³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13104440312195 and 13104440312204.

It is not an unprimeable number, because it can be changed into a prime (13104440312213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82277185 + ... + 82436302.

It is an arithmetic number, because the mean of its divisors is an integer number (3276151276320).

Almost surely, 2^{13104440312233} is an apocalyptic number.

It is an amenable number.

13104440312233 is a deficient number, since it is larger than the sum of its proper divisors (164793047).

13104440312233 is an equidigital number, since it uses as much as digits as its factorization.

13104440312233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 164793046.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13104440312233 its reverse (33221304440131), we get a palindrome (46325744752364).

The spelling of 13104440312233 in words is "thirteen trillion, one hundred four billion, four hundred forty million, three hundred twelve thousand, two hundred thirty-three".