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131044404013034 = 265522202006517
BaseRepresentation
bin11101110010111100100111…
…001001101010011111101010
3122011222201111211102021220012
4131302330213021222133222
5114134012414411404114
61142412545040331522
736413434331302451
oct3562744711523752
9564881454367805
10131044404013034
113883368a821356
1212845349913ba2
13581758513ca45
142450823a53b98
151023b7427463e
hex772f2726a7ea

131044404013034 has 4 divisors (see below), whose sum is σ = 196566606019554. Its totient is φ = 65522202006516.

The previous prime is 131044404013031. The next prime is 131044404013057. The reversal of 131044404013034 is 430310404440131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 130091931466225 + 952472546809 = 11405785^2 + 975947^2 .

It is not an unprimeable number, because it can be changed into a prime (131044404013031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32761101003257 + ... + 32761101003260.

Almost surely, 2131044404013034 is an apocalyptic number.

131044404013034 is a deficient number, since it is larger than the sum of its proper divisors (65522202006520).

131044404013034 is an equidigital number, since it uses as much as digits as its factorization.

131044404013034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65522202006519.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 131044404013034 its reverse (430310404440131), we get a palindrome (561354808453165).

The spelling of 131044404013034 in words is "one hundred thirty-one trillion, forty-four billion, four hundred four million, thirteen thousand, thirty-four".

Divisors: 1 2 65522202006517 131044404013034