Base | Representation |
---|---|
bin | 1011111010110010001001… |
… | …0001001101000100110010 |
3 | 1201101210001112121120002201 |
4 | 2332230202101031010302 |
5 | 3204201024124433232 |
6 | 43512044454133414 |
7 | 2521525140304552 |
oct | 276544221150462 |
9 | 51353045546081 |
10 | 13104520155442 |
11 | 41a2660aa2551 |
12 | 15778b135126a |
13 | 74099baaa741 |
14 | 33439551b162 |
15 | 17ad2a641be7 |
hex | beb2244d132 |
13104520155442 has 4 divisors (see below), whose sum is σ = 19656780233166. Its totient is φ = 6552260077720.
The previous prime is 13104520155403. The next prime is 13104520155491. The reversal of 13104520155442 is 24455102540131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8644605509241 + 4459914646201 = 2940171^2 + 2111851^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3276130038859 + ... + 3276130038862.
Almost surely, 213104520155442 is an apocalyptic number.
13104520155442 is a deficient number, since it is larger than the sum of its proper divisors (6552260077724).
13104520155442 is an equidigital number, since it uses as much as digits as its factorization.
13104520155442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6552260077723.
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 13104520155442 its reverse (24455102540131), we get a palindrome (37559622695573).
The spelling of 13104520155442 in words is "thirteen trillion, one hundred four billion, five hundred twenty million, one hundred fifty-five thousand, four hundred forty-two".
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