Base | Representation |
---|---|
bin | 1011111010110010001001… |
… | …0001011000110100010011 |
3 | 1201101210001112201000002002 |
4 | 2332230202101120310103 |
5 | 3204201024133003124 |
6 | 43512044455144215 |
7 | 2521525140565022 |
oct | 276544221306423 |
9 | 51353045630062 |
10 | 13104520203539 |
11 | 41a26610256a6 |
12 | 15778b137506b |
13 | 74099bac65bb |
14 | 3343955308b9 |
15 | 17ad2a6510ae |
hex | beb22458d13 |
13104520203539 has 2 divisors, whose sum is σ = 13104520203540. Its totient is φ = 13104520203538.
The previous prime is 13104520203499. The next prime is 13104520203641. The reversal of 13104520203539 is 93530202540131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13104520203539 is a prime.
It is a super-3 number, since 3×131045202035393 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13104520223539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552260101769 + 6552260101770.
It is an arithmetic number, because the mean of its divisors is an integer number (6552260101770).
Almost surely, 213104520203539 is an apocalyptic number.
13104520203539 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104520203539 is an equidigital number, since it uses as much as digits as its factorization.
13104520203539 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97200, while the sum is 38.
The spelling of 13104520203539 in words is "thirteen trillion, one hundred four billion, five hundred twenty million, two hundred three thousand, five hundred thirty-nine".
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