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13104531205561 is a prime number
BaseRepresentation
bin1011111010110010001011…
…1011010110110110111001
31201101210002022101222000101
42332230202323112312321
53204201034442034221
643512045531035401
72521525333236625
oct276544273266671
951353068358011
1013104531205561
1141a266725a684
1215778b4b9bb61
137409a1179283
14334396b96185
1517ad2b5c5d91
hexbeb22ed6db9

13104531205561 has 2 divisors, whose sum is σ = 13104531205562. Its totient is φ = 13104531205560.

The previous prime is 13104531205487. The next prime is 13104531205589. The reversal of 13104531205561 is 16550213540131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12922335405225 + 182195800336 = 3594765^2 + 426844^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104531205561 - 217 = 13104531074489 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13104531205561.

It is not a weakly prime, because it can be changed into another prime (13104531202561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552265602780 + 6552265602781.

It is an arithmetic number, because the mean of its divisors is an integer number (6552265602781).

Almost surely, 213104531205561 is an apocalyptic number.

It is an amenable number.

13104531205561 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104531205561 is an equidigital number, since it uses as much as digits as its factorization.

13104531205561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54000, while the sum is 37.

Adding to 13104531205561 its reverse (16550213540131), we get a palindrome (29654744745692).

The spelling of 13104531205561 in words is "thirteen trillion, one hundred four billion, five hundred thirty-one million, two hundred five thousand, five hundred sixty-one".