Base | Representation |
---|---|
bin | 11101110010111101011110… |
… | …000000110001101110101010 |
3 | 122011222210212222100022221201 |
4 | 131302331132000301232222 |
5 | 114134021311023232000 |
6 | 1142413220240154414 |
7 | 36413466205565536 |
oct | 3562753600615652 |
9 | 564883788308851 |
10 | 131045324430250 |
11 | 3883401232943a |
12 | 12845566008a0a |
13 | 58176a0a34709 |
14 | 24508adda6bc6 |
15 | 1023bc9e8596a |
hex | 772f5e031baa |
131045324430250 has 32 divisors (see below), whose sum is σ = 245596570489296. Its totient is φ = 52358359867200.
The previous prime is 131045324430221. The next prime is 131045324430259. The reversal of 131045324430250 is 52034423540131.
It can be written as a sum of positive squares in 8 ways, for example, as 47324892317481 + 83720432112769 = 6879309^2 + 9149887^2 .
It is not an unprimeable number, because it can be changed into a prime (131045324430259) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 298629837 + ... + 299068336.
Almost surely, 2131045324430250 is an apocalyptic number.
131045324430250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131045324430250 is a deficient number, since it is larger than the sum of its proper divisors (114551246059046).
131045324430250 is an equidigital number, since it uses as much as digits as its factorization.
131045324430250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 597699067 (or 597699057 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 131045324430250 its reverse (52034423540131), we get a palindrome (183079747970381).
The spelling of 131045324430250 in words is "one hundred thirty-one trillion, forty-five billion, three hundred twenty-four million, four hundred thirty thousand, two hundred fifty".
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