Base | Representation |
---|---|
bin | 111101000001011110… |
… | …1100110101111010011 |
3 | 110112020211120001000201 |
4 | 1322002331212233103 |
5 | 4121340312101134 |
6 | 140111331000031 |
7 | 12316306242562 |
oct | 1720275465723 |
9 | 415224501021 |
10 | 131046206419 |
11 | 50638192537 |
12 | 21493139017 |
13 | c48586c49b |
14 | 64b2403bd9 |
15 | 361eb20914 |
hex | 1e82f66bd3 |
131046206419 has 2 divisors, whose sum is σ = 131046206420. Its totient is φ = 131046206418.
The previous prime is 131046206399. The next prime is 131046206429. The reversal of 131046206419 is 914602640131.
It is a strong prime.
It is an emirp because it is prime and its reverse (914602640131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131046206419 - 211 = 131046204371 is a prime.
It is a super-2 number, since 2×1310462064192 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131046206429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65523103209 + 65523103210.
It is an arithmetic number, because the mean of its divisors is an integer number (65523103210).
Almost surely, 2131046206419 is an apocalyptic number.
131046206419 is a deficient number, since it is larger than the sum of its proper divisors (1).
131046206419 is an equidigital number, since it uses as much as digits as its factorization.
131046206419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 37.
The spelling of 131046206419 in words is "one hundred thirty-one billion, forty-six million, two hundred six thousand, four hundred nineteen".
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