1310499481 has 2 divisors, whose sum is σ = 1310499482. Its totient is φ = 1310499480.

The previous prime is 1310499427. The next prime is 1310499493. The reversal of 1310499481 is 1849940131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1145145600 + 165353881 = 33840^2 + 12859^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310499481 - 2¹³ = 1310491289 is a prime.

It is a super-2 number, since 2×1310499481² = 3434817779402538722, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1310409481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655249740 + 655249741.

It is an arithmetic number, because the mean of its divisors is an integer number (655249741).

Almost surely, 2^1310499481 is an apocalyptic number.

It is an amenable number.

1310499481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310499481 is an equidigital number, since it uses as much as digits as its factorization.

1310499481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 40.

The square root of 1310499481 is about 36200.8215514510. The cubic root of 1310499481 is about 1094.3232283772.

The spelling of 1310499481 in words is "one billion, three hundred ten million, four hundred ninety-nine thousand, four hundred eighty-one".