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13105145030611 = 63103207678637
BaseRepresentation
bin1011111010110100011110…
…0000111010011111010011
31201101211200002102111200111
42332231013200322133103
53204203314111434421
643512230455302151
72521546465536214
oct276550740723723
951354602374614
1013105145030611
1141a29517a0507
121577a4667a957
13740a6b3a576a
143344144db40b
1517ad65424ee1
hexbeb4783a7d3

13105145030611 has 4 divisors (see below), whose sum is σ = 13105352772352. Its totient is φ = 13104937288872.

The previous prime is 13105145030609. The next prime is 13105145030629. The reversal of 13105145030611 is 11603054150131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13105145030611 - 21 = 13105145030609 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13105145030711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103776216 + ... + 103902421.

It is an arithmetic number, because the mean of its divisors is an integer number (3276338193088).

Almost surely, 213105145030611 is an apocalyptic number.

13105145030611 is a deficient number, since it is larger than the sum of its proper divisors (207741741).

13105145030611 is an equidigital number, since it uses as much as digits as its factorization.

13105145030611 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 207741740.

The product of its (nonzero) digits is 5400, while the sum is 31.

Adding to 13105145030611 its reverse (11603054150131), we get a palindrome (24708199180742).

The spelling of 13105145030611 in words is "thirteen trillion, one hundred five billion, one hundred forty-five million, thirty thousand, six hundred eleven".

Divisors: 1 63103 207678637 13105145030611