Base | Representation |
---|---|
bin | 1011111010110101001100… |
… | …1010101111100001011001 |
3 | 1201101212011201022200011100 |
4 | 2332231103022233201121 |
5 | 3204204214134420423 |
6 | 43512302122022013 |
7 | 2521554361432305 |
oct | 276552312574131 |
9 | 51355151280140 |
10 | 13105340545113 |
11 | 41a2a4209a443 |
12 | 1577aa0047909 |
13 | 740a9ca4c20b |
14 | 334432472d05 |
15 | 17ad77695343 |
hex | beb532af859 |
13105340545113 has 24 divisors (see below), whose sum is σ = 19339197995520. Its totient is φ = 8549961114240.
The previous prime is 13105340545103. The next prime is 13105340545117. The reversal of 13105340545113 is 31154504350131.
13105340545113 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 53 + 40 + 54 + 511 + 3 = 666.
It is not a de Polignac number, because 13105340545113 - 214 = 13105340528729 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13105340545117) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 81478353 + ... + 81639038.
It is an arithmetic number, because the mean of its divisors is an integer number (805799916480).
Almost surely, 213105340545113 is an apocalyptic number.
It is an amenable number.
13105340545113 is a deficient number, since it is larger than the sum of its proper divisors (6233857450407).
13105340545113 is a wasteful number, since it uses less digits than its factorization.
13105340545113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 163117589 (or 163117586 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 36.
Adding to 13105340545113 its reverse (31154504350131), we get a palindrome (44259844895244).
The spelling of 13105340545113 in words is "thirteen trillion, one hundred five billion, three hundred forty million, five hundred forty-five thousand, one hundred thirteen".
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