Base | Representation |
---|---|
bin | 10011000100100010000… |
… | …001110100000011001001 |
3 | 11122021201111112221120012 |
4 | 103010202001310003021 |
5 | 132432434144112321 |
6 | 2442015113041305 |
7 | 163453205366603 |
oct | 23044201640311 |
9 | 4567644487505 |
10 | 1310535925961 |
11 | 465882401319 |
12 | 191ba79b6235 |
13 | 96776b38062 |
14 | 47604976173 |
15 | 24153d9605b |
hex | 131220740c9 |
1310535925961 has 2 divisors, whose sum is σ = 1310535925962. Its totient is φ = 1310535925960.
The previous prime is 1310535925949. The next prime is 1310535925991. The reversal of 1310535925961 is 1695295350131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1250022385936 + 60513540025 = 1118044^2 + 245995^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310535925961 - 218 = 1310535663817 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310535925991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655267962980 + 655267962981.
It is an arithmetic number, because the mean of its divisors is an integer number (655267962981).
Almost surely, 21310535925961 is an apocalyptic number.
It is an amenable number.
1310535925961 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310535925961 is an equidigital number, since it uses as much as digits as its factorization.
1310535925961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1093500, while the sum is 50.
The spelling of 1310535925961 in words is "one trillion, three hundred ten billion, five hundred thirty-five million, nine hundred twenty-five thousand, nine hundred sixty-one".
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