Base | Representation |
---|---|
bin | 10011000100100010010… |
… | …110100001100110111011 |
3 | 11122021201212202210102102 |
4 | 103010202112201212323 |
5 | 132432442041333301 |
6 | 2442015425254015 |
7 | 163453302502166 |
oct | 23044226414673 |
9 | 4567655683372 |
10 | 1310541355451 |
11 | 46588547a5a9 |
12 | 191ba979430b |
13 | 96777cb9483 |
14 | 4760558aadd |
15 | 241545b9b6b |
hex | 131225a19bb |
1310541355451 has 2 divisors, whose sum is σ = 1310541355452. Its totient is φ = 1310541355450.
The previous prime is 1310541355369. The next prime is 1310541355493. The reversal of 1310541355451 is 1545531450131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1310541355451 - 210 = 1310541354427 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310541355951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655270677725 + 655270677726.
It is an arithmetic number, because the mean of its divisors is an integer number (655270677726).
Almost surely, 21310541355451 is an apocalyptic number.
1310541355451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310541355451 is an equidigital number, since it uses as much as digits as its factorization.
1310541355451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90000, while the sum is 38.
The spelling of 1310541355451 in words is "one trillion, three hundred ten billion, five hundred forty-one million, three hundred fifty-five thousand, four hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •