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13105434353243 = 412669471197409
BaseRepresentation
bin1011111010110101100011…
…0000100101111001011011
31201101212102020211121201112
42332231120300211321123
53204204412143300433
643512315312410535
72521556610665351
oct276553060457133
951355366747645
1013105434353243
1141a2a90041921
121577b07546a4b
13740ab630559b
14334440ad17d1
1517ad80a25348
hexbeb58c25e5b

13105434353243 has 8 divisors (see below), whose sum is σ = 13425140596560. Its totient is φ = 12785731038720.

The previous prime is 13105434353113. The next prime is 13105434353251. The reversal of 13105434353243 is 34235343450131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13105434353243 - 226 = 13105367244379 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (41).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13105434353243.

It is not an unprimeable number, because it can be changed into a prime (13105434358243) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10346123 + ... + 11543531.

It is an arithmetic number, because the mean of its divisors is an integer number (1678142574570).

Almost surely, 213105434353243 is an apocalyptic number.

13105434353243 is a deficient number, since it is larger than the sum of its proper divisors (319706243317).

13105434353243 is a wasteful number, since it uses less digits than its factorization.

13105434353243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1464397.

The product of its (nonzero) digits is 777600, while the sum is 41.

The spelling of 13105434353243 in words is "thirteen trillion, one hundred five billion, four hundred thirty-four million, three hundred fifty-three thousand, two hundred forty-three".

Divisors: 1 41 266947 1197409 10944827 49093769 319644740323 13105434353243