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13105442544521 is a prime number
BaseRepresentation
bin1011111010110101100100…
…1111110101101110001001
31201101212102211020210001012
42332231121033311232021
53204204421242411041
643512320204133305
72521560040422545
oct276553117655611
951355384223035
1013105442544521
1141a2a94727078
121577b0a237235
13740ab7c12ab2
14334441c24a25
1517ad815e23eb
hexbeb593f5b89

13105442544521 has 2 divisors, whose sum is σ = 13105442544522. Its totient is φ = 13105442544520.

The previous prime is 13105442544517. The next prime is 13105442544589. The reversal of 13105442544521 is 12544524450131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12385922964496 + 719519580025 = 3519364^2 + 848245^2 .

It is a cyclic number.

It is not a de Polignac number, because 13105442544521 - 22 = 13105442544517 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13105442544721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552721272260 + 6552721272261.

It is an arithmetic number, because the mean of its divisors is an integer number (6552721272261).

Almost surely, 213105442544521 is an apocalyptic number.

It is an amenable number.

13105442544521 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105442544521 is an equidigital number, since it uses as much as digits as its factorization.

13105442544521 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384000, while the sum is 41.

Adding to 13105442544521 its reverse (12544524450131), we get a palindrome (25649966994652).

The spelling of 13105442544521 in words is "thirteen trillion, one hundred five billion, four hundred forty-two million, five hundred forty-four thousand, five hundred twenty-one".