Base | Representation |
---|---|
bin | 1011111010110101100101… |
… | …0010110011011001000011 |
3 | 1201101212102212201020201220 |
4 | 2332231121102303121003 |
5 | 3204204421442241121 |
6 | 43512320232530123 |
7 | 2521560050136540 |
oct | 276553122633103 |
9 | 51355385636656 |
10 | 13105443321411 |
11 | 41a2a95107831 |
12 | 1577b0a550943 |
13 | 740ab81255ac |
14 | 334441d87bc7 |
15 | 17ad816e76c6 |
hex | beb594b3643 |
13105443321411 has 32 divisors (see below), whose sum is σ = 20049343277568. Its totient is φ = 7459182432000.
The previous prime is 13105443321389. The next prime is 13105443321433. The reversal of 13105443321411 is 11412334450131.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (13105443321389) and next prime (13105443321433).
It is not a de Polignac number, because 13105443321411 - 211 = 13105443319363 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13105443321211) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7828161 + ... + 9353661.
It is an arithmetic number, because the mean of its divisors is an integer number (626541977424).
Almost surely, 213105443321411 is an apocalyptic number.
13105443321411 is a deficient number, since it is larger than the sum of its proper divisors (6943899956157).
13105443321411 is a wasteful number, since it uses less digits than its factorization.
13105443321411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1527131.
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 13105443321411 its reverse (11412334450131), we get a palindrome (24517777771542).
The spelling of 13105443321411 in words is "thirteen trillion, one hundred five billion, four hundred forty-three million, three hundred twenty-one thousand, four hundred eleven".
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