13105451153441 has 2 divisors, whose sum is σ = 13105451153442. Its totient is φ = 13105451153440.

The previous prime is 13105451153369. The next prime is 13105451153471. The reversal of 13105451153441 is 14435115450131.

13105451153441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11911326735841 + 1194124417600 = 3451279^2 + 1092760^2 .

It is a cyclic number.

It is not a de Polignac number, because 13105451153441 - 2¹⁸ = 13105450891297 is a prime.

It is a super-2 number, since 2×13105451153441² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13105451153395 and 13105451153404.

It is not a weakly prime, because it can be changed into another prime (13105451153471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552725576720 + 6552725576721.

It is an arithmetic number, because the mean of its divisors is an integer number (6552725576721).

Almost surely, 2^{13105451153441} is an apocalyptic number.

It is an amenable number.

13105451153441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105451153441 is an equidigital number, since it uses as much as digits as its factorization.

13105451153441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72000, while the sum is 38.

The spelling of 13105451153441 in words is "thirteen trillion, one hundred five billion, four hundred fifty-one million, one hundred fifty-three thousand, four hundred forty-one".