Base | Representation |
---|---|
bin | 11000011010010110… |
… | …11110000101010001 |
3 | 1020211101021102021021 |
4 | 30031023132011101 |
5 | 203320114344442 |
6 | 10004255155441 |
7 | 642531160654 |
oct | 141513360521 |
9 | 36741242237 |
10 | 13106012497 |
11 | 5616003196 |
12 | 2659215b81 |
13 | 130b33c0a6 |
14 | 8c488389b |
15 | 51a8e2e67 |
hex | 30d2de151 |
13106012497 has 2 divisors, whose sum is σ = 13106012498. Its totient is φ = 13106012496.
The previous prime is 13106012483. The next prime is 13106012501. The reversal of 13106012497 is 79421060131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12895646481 + 210366016 = 113559^2 + 14504^2 .
It is a cyclic number.
It is not a de Polignac number, because 13106012497 - 215 = 13105979729 is a prime.
It is not a weakly prime, because it can be changed into another prime (13106012897) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6553006248 + 6553006249.
It is an arithmetic number, because the mean of its divisors is an integer number (6553006249).
Almost surely, 213106012497 is an apocalyptic number.
It is an amenable number.
13106012497 is a deficient number, since it is larger than the sum of its proper divisors (1).
13106012497 is an equidigital number, since it uses as much as digits as its factorization.
13106012497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 34.
The spelling of 13106012497 in words is "thirteen billion, one hundred six million, twelve thousand, four hundred ninety-seven".
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