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131065243577 is a prime number
BaseRepresentation
bin111101000010000011…
…0001110011110111001
3110112022011101020002122
41322010012032132321
54121410200243302
6140113251011025
712316630121522
oct1720406163671
9415264336078
10131065243577
1150647a05424
1221499599a75
13c4897a6588
1464b4b5b849
1536216313a2
hex1e8418e7b9

131065243577 has 2 divisors, whose sum is σ = 131065243578. Its totient is φ = 131065243576.

The previous prime is 131065243483. The next prime is 131065243649. The reversal of 131065243577 is 775342560131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118218381241 + 12846862336 = 343829^2 + 113344^2 .

It is a cyclic number.

It is not a de Polignac number, because 131065243577 - 220 = 131064195001 is a prime.

It is not a weakly prime, because it can be changed into another prime (131065248577) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65532621788 + 65532621789.

It is an arithmetic number, because the mean of its divisors is an integer number (65532621789).

Almost surely, 2131065243577 is an apocalyptic number.

It is an amenable number.

131065243577 is a deficient number, since it is larger than the sum of its proper divisors (1).

131065243577 is an equidigital number, since it uses as much as digits as its factorization.

131065243577 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 529200, while the sum is 44.

The spelling of 131065243577 in words is "one hundred thirty-one billion, sixty-five million, two hundred forty-three thousand, five hundred seventy-seven".