Base | Representation |
---|---|
bin | 10011000100110100001… |
… | …011110110100110110001 |
3 | 11122022111201202100010002 |
4 | 103010310023312212301 |
5 | 132434100140012021 |
6 | 2442105234115345 |
7 | 163463564546033 |
oct | 23046413664661 |
9 | 4568451670102 |
10 | 1310840547761 |
11 | 465a19352178 |
12 | 192071a1bb55 |
13 | 967c4c93744 |
14 | 476331cdc53 |
15 | 241709b950b |
hex | 131342f69b1 |
1310840547761 has 2 divisors, whose sum is σ = 1310840547762. Its totient is φ = 1310840547760.
The previous prime is 1310840547701. The next prime is 1310840547767. The reversal of 1310840547761 is 1677450480131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1231178872225 + 79661675536 = 1109585^2 + 282244^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310840547761 - 234 = 1293660678577 is a prime.
It is a super-2 number, since 2×13108405477612 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310840547767) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655420273880 + 655420273881.
It is an arithmetic number, because the mean of its divisors is an integer number (655420273881).
Almost surely, 21310840547761 is an apocalyptic number.
It is an amenable number.
1310840547761 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310840547761 is an equidigital number, since it uses as much as digits as its factorization.
1310840547761 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 564480, while the sum is 47.
The spelling of 1310840547761 in words is "one trillion, three hundred ten billion, eight hundred forty million, five hundred forty-seven thousand, seven hundred sixty-one".
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