Base | Representation |
---|---|
bin | 111101000010101001… |
… | …0001010100011000011 |
3 | 110112100112211121010111 |
4 | 1322011102022203003 |
5 | 4121430244303103 |
6 | 140115241412151 |
7 | 12320261252104 |
oct | 1720522124303 |
9 | 415315747114 |
10 | 131085150403 |
11 | 50658171749 |
12 | 214a419a057 |
13 | c49095646c |
14 | 64b76603ab |
15 | 362326486d |
hex | 1e8548a8c3 |
131085150403 has 2 divisors, whose sum is σ = 131085150404. Its totient is φ = 131085150402.
The previous prime is 131085150397. The next prime is 131085150439. The reversal of 131085150403 is 304051580131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131085150403 - 213 = 131085142211 is a prime.
It is not a weakly prime, because it can be changed into another prime (131085153403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65542575201 + 65542575202.
It is an arithmetic number, because the mean of its divisors is an integer number (65542575202).
Almost surely, 2131085150403 is an apocalyptic number.
131085150403 is a deficient number, since it is larger than the sum of its proper divisors (1).
131085150403 is an equidigital number, since it uses as much as digits as its factorization.
131085150403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
The spelling of 131085150403 in words is "one hundred thirty-one billion, eighty-five million, one hundred fifty thousand, four hundred three".
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