Search a number
-
+
13109923331 is a prime number
BaseRepresentation
bin11000011010110100…
…11000111000000011
31020211122122002220222
430031122120320003
5203322120021311
610004515053255
7642606336551
oct141532307003
936748562828
1013109923331
11561823448a
12265a5a122b
13130c0ab1ab
148c51c0bd1
1551ae16adb
hex30d698e03

13109923331 has 2 divisors, whose sum is σ = 13109923332. Its totient is φ = 13109923330.

The previous prime is 13109923283. The next prime is 13109923391. The reversal of 13109923331 is 13332990131.

It is a weak prime.

It is an emirp because it is prime and its reverse (13332990131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13109923331 - 222 = 13105729027 is a prime.

It is a super-2 number, since 2×131099233312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13109923291 and 13109923300.

It is not a weakly prime, because it can be changed into another prime (13109923391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6554961665 + 6554961666.

It is an arithmetic number, because the mean of its divisors is an integer number (6554961666).

Almost surely, 213109923331 is an apocalyptic number.

13109923331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13109923331 is an equidigital number, since it uses as much as digits as its factorization.

13109923331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13122, while the sum is 35.

The spelling of 13109923331 in words is "thirteen billion, one hundred nine million, nine hundred twenty-three thousand, three hundred thirty-one".