13110011213001 has 4 divisors (see below), whose sum is σ = 17480014950672. Its totient is φ = 8740007475332.

The previous prime is 13110011212951. The next prime is 13110011213071. The reversal of 13110011213001 is 10031211001131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110011213001 - 2⁴¹ = 10910987957449 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13110011213071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185001868831 + ... + 2185001868836.

It is an arithmetic number, because the mean of its divisors is an integer number (4370003737668).

Almost surely, 2^{13110011213001} is an apocalyptic number.

It is an amenable number.

13110011213001 is a deficient number, since it is larger than the sum of its proper divisors (4370003737671).

13110011213001 is an equidigital number, since it uses as much as digits as its factorization.

13110011213001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4370003737670.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 13110011213001 its reverse (10031211001131), we get a palindrome (23141222214132).

The spelling of 13110011213001 in words is "thirteen trillion, one hundred ten billion, eleven million, two hundred thirteen thousand, one".