13110033312001 has 4 divisors (see below), whose sum is σ = 13110040753600. Its totient is φ = 13110025870404.

The previous prime is 13110033311987. The next prime is 13110033312007. The reversal of 13110033312001 is 10021333001131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13110033312001 - 2¹¹ = 13110033309953 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13110033312001.

It is not an unprimeable number, because it can be changed into a prime (13110033312007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 575020 + ... + 5152738.

It is an arithmetic number, because the mean of its divisors is an integer number (3277510188400).

Almost surely, 2^{13110033312001} is an apocalyptic number.

It is an amenable number.

13110033312001 is a deficient number, since it is larger than the sum of its proper divisors (7441599).

13110033312001 is an equidigital number, since it uses as much as digits as its factorization.

13110033312001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7441598.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13110033312001 its reverse (10021333001131), we get a palindrome (23131366313132).

The spelling of 13110033312001 in words is "thirteen trillion, one hundred ten billion, thirty-three million, three hundred twelve thousand, one".