Base | Representation |
---|---|
bin | 10011000100111110010… |
… | …010110000100010100011 |
3 | 11122022221112212000022211 |
4 | 103010332102300202203 |
5 | 132434422043130313 |
6 | 2442134132542551 |
7 | 163501024145113 |
oct | 23047622604243 |
9 | 4568845760284 |
10 | 1311010130083 |
11 | 465aa6049955 |
12 | 1920ba781a57 |
13 | 9682115a904 |
14 | 4764b935043 |
15 | 24180815e3d |
hex | 1313e4b08a3 |
1311010130083 has 2 divisors, whose sum is σ = 1311010130084. Its totient is φ = 1311010130082.
The previous prime is 1311010130057. The next prime is 1311010130117. The reversal of 1311010130083 is 3800310101131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311010130083 is a prime.
It is a super-2 number, since 2×13110101300832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1311010131083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655505065041 + 655505065042.
It is an arithmetic number, because the mean of its divisors is an integer number (655505065042).
Almost surely, 21311010130083 is an apocalyptic number.
1311010130083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311010130083 is an equidigital number, since it uses as much as digits as its factorization.
1311010130083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 22.
The spelling of 1311010130083 in words is "one trillion, three hundred eleven billion, ten million, one hundred thirty thousand, eighty-three".
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