Base | Representation |
---|---|
bin | 10011000100111110010… |
… | …011000100100100100101 |
3 | 11122022221120000011212201 |
4 | 103010332103010210211 |
5 | 132434422103242013 |
6 | 2442134134414501 |
7 | 163501024636246 |
oct | 23047623044445 |
9 | 4568846004781 |
10 | 1311010212133 |
11 | 465aa60a5566 |
12 | 1920ba801431 |
13 | 9682118906b |
14 | 4764b956ccd |
15 | 241808303dd |
hex | 1313e4c4925 |
1311010212133 has 16 divisors (see below), whose sum is σ = 1340954081280. Its totient is φ = 1281374780400.
The previous prime is 1311010212067. The next prime is 1311010212173. The reversal of 1311010212133 is 3312120101131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311010212133 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1311010212133.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311010212173) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 104782348 + ... + 104794858.
It is an arithmetic number, because the mean of its divisors is an integer number (83809630080).
Almost surely, 21311010212133 is an apocalyptic number.
It is an amenable number.
1311010212133 is a deficient number, since it is larger than the sum of its proper divisors (29943869147).
1311010212133 is a wasteful number, since it uses less digits than its factorization.
1311010212133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24648.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1311010212133 its reverse (3312120101131), we get a palindrome (4623130313264).
The spelling of 1311010212133 in words is "one trillion, three hundred eleven billion, ten million, two hundred twelve thousand, one hundred thirty-three".
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