Base | Representation |
---|---|
bin | 10011000100111110010… |
… | …011011100011111110011 |
3 | 11122022221120012011022021 |
4 | 103010332103130133303 |
5 | 132434422114411011 |
6 | 2442134140452311 |
7 | 163501025525044 |
oct | 23047623343763 |
9 | 4568846164267 |
10 | 1311010310131 |
11 | 465aa6162155 |
12 | 1920ba84a097 |
13 | 968211c1852 |
14 | 4764b9808cb |
15 | 2418084e471 |
hex | 1313e4dc7f3 |
1311010310131 has 8 divisors (see below), whose sum is σ = 1317035009520. Its totient is φ = 1304998666752.
The previous prime is 1311010310089. The next prime is 1311010310161. The reversal of 1311010310131 is 1310130101131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311010310131 is a prime.
It is a super-3 number, since 3×13110103101313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1311010310161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3062685 + ... + 3464398.
It is an arithmetic number, because the mean of its divisors is an integer number (164629376190).
Almost surely, 21311010310131 is an apocalyptic number.
1311010310131 is a deficient number, since it is larger than the sum of its proper divisors (6024699389).
1311010310131 is an equidigital number, since it uses as much as digits as its factorization.
1311010310131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6528005.
The product of its (nonzero) digits is 27, while the sum is 16.
Adding to 1311010310131 its reverse (1310130101131), we get a palindrome (2621140411262).
The spelling of 1311010310131 in words is "one trillion, three hundred eleven billion, ten million, three hundred ten thousand, one hundred thirty-one".
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