131101103113 has 2 divisors, whose sum is σ = 131101103114. Its totient is φ = 131101103112.

The previous prime is 131101103099. The next prime is 131101103117. The reversal of 131101103113 is 311301101131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121624470009 + 9476633104 = 348747^2 + 97348^2 .

It is an emirp because it is prime and its reverse (311301101131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131101103113 is a prime.

It is not a weakly prime, because it can be changed into another prime (131101103117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550551556 + 65550551557.

It is an arithmetic number, because the mean of its divisors is an integer number (65550551557).

Almost surely, 2^131101103113 is an apocalyptic number.

It is an amenable number.

131101103113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101103113 is an equidigital number, since it uses as much as digits as its factorization.

131101103113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 131101103113 its reverse (311301101131), we get a palindrome (442402204244).

The spelling of 131101103113 in words is "one hundred thirty-one billion, one hundred one million, one hundred three thousand, one hundred thirteen".