13110110413441 has 2 divisors, whose sum is σ = 13110110413442. Its totient is φ = 13110110413440.

The previous prime is 13110110413429. The next prime is 13110110413469. The reversal of 13110110413441 is 14431401101131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11156835834225 + 1953274579216 = 3340185^2 + 1397596^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110110413441 - 2¹¹ = 13110110411393 is a prime.

It is a super-2 number, since 2×13110110413441² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13110110417441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555055206720 + 6555055206721.

It is an arithmetic number, because the mean of its divisors is an integer number (6555055206721).

Almost surely, 2^{13110110413441} is an apocalyptic number.

It is an amenable number.

13110110413441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110110413441 is an equidigital number, since it uses as much as digits as its factorization.

13110110413441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 13110110413441 its reverse (14431401101131), we get a palindrome (27541511514572).

The spelling of 13110110413441 in words is "thirteen trillion, one hundred ten billion, one hundred ten million, four hundred thirteen thousand, four hundred forty-one".