Base | Representation |
---|---|
bin | 1011111011000111000000… |
… | …1111100101001011000100 |
3 | 1201102022112000221210220010 |
4 | 2332301300033211023010 |
5 | 3204244013032220004 |
6 | 43514412453310220 |
7 | 2522114035361364 |
oct | 276616017451304 |
9 | 51368460853803 |
10 | 13110123320004 |
11 | 41a4a76919a67 |
12 | 15789b5935370 |
13 | 7413828a2429 |
14 | 33476774a9a4 |
15 | 17b0574dda89 |
hex | bec703e52c4 |
13110123320004 has 24 divisors (see below), whose sum is σ = 30590365151808. Its totient is φ = 4370030048800.
The previous prime is 13110123319981. The next prime is 13110123320009. The reversal of 13110123320004 is 40002332101131.
13110123320004 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (13110123320009) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4589854 + ... + 6876554.
It is an arithmetic number, because the mean of its divisors is an integer number (1274598547992).
Almost surely, 213110123320004 is an apocalyptic number.
It is an amenable number.
13110123320004 is an abundant number, since it is smaller than the sum of its proper divisors (17480241831804).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110123320004 is a wasteful number, since it uses less digits than its factorization.
13110123320004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2764475 (or 2764473 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13110123320004 its reverse (40002332101131), we get a palindrome (53112455421135).
The spelling of 13110123320004 in words is "thirteen trillion, one hundred ten billion, one hundred twenty-three million, three hundred twenty thousand, four".
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