13110131113 has 4 divisors (see below), whose sum is σ = 13112983888. Its totient is φ = 13107278340.

The previous prime is 13110131071. The next prime is 13110131129. The reversal of 13110131113 is 31113101131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13110131113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13110131173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1419483 + ... + 1428688.

It is an arithmetic number, because the mean of its divisors is an integer number (3278245972).

Almost surely, 2^13110131113 is an apocalyptic number.

It is an amenable number.

13110131113 is a deficient number, since it is larger than the sum of its proper divisors (2852775).

13110131113 is an equidigital number, since it uses as much as digits as its factorization.

13110131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2852774.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 13110131113 its reverse (31113101131), we get a palindrome (44223232244).

The spelling of 13110131113 in words is "thirteen billion, one hundred ten million, one hundred thirty-one thousand, one hundred thirteen".