Base | Representation |
---|---|
bin | 11101110011110001101000… |
… | …011101111100100111101100 |
3 | 122012012011110102000211011022 |
4 | 131303301220131330213230 |
5 | 114140431013103032134 |
6 | 1142455042132513312 |
7 | 36420521165642225 |
oct | 3563615035744754 |
9 | 565164412024138 |
10 | 131101334424044 |
11 | 38855844528806 |
12 | 1285439777b838 |
13 | 581ca5895bc8a |
14 | 24534a498824c |
15 | 10253a728952e |
hex | 773c6877c9ec |
131101334424044 has 6 divisors (see below), whose sum is σ = 229427335242084. Its totient is φ = 65550667212020.
The previous prime is 131101334424043. The next prime is 131101334424059. The reversal of 131101334424044 is 440424433101131.
It is a junction number, because it is equal to n+sod(n) for n = 131101334423995 and 131101334424013.
It is not an unprimeable number, because it can be changed into a prime (131101334424043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16387666803002 + ... + 16387666803009.
It is an arithmetic number, because the mean of its divisors is an integer number (38237889207014).
Almost surely, 2131101334424044 is an apocalyptic number.
It is an amenable number.
131101334424044 is a deficient number, since it is larger than the sum of its proper divisors (98326000818040).
131101334424044 is a wasteful number, since it uses less digits than its factorization.
131101334424044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32775333606015 (or 32775333606013 counting only the distinct ones).
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 131101334424044 its reverse (440424433101131), we get a palindrome (571525767525175).
The spelling of 131101334424044 in words is "one hundred thirty-one trillion, one hundred one billion, three hundred thirty-four million, four hundred twenty-four thousand, forty-four".
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