Base | Representation |
---|---|
bin | 11101110011110001101000… |
… | …111111000101100010101100 |
3 | 122012012011111000101011220000 |
4 | 131303301220333011202230 |
5 | 114140431022314030330 |
6 | 1142455043043024300 |
7 | 36420521332533510 |
oct | 3563615077054254 |
9 | 565164430334800 |
10 | 131101343111340 |
11 | 38855849421698 |
12 | 1285439a66b090 |
13 | 581ca5a6b11a4 |
14 | 24534a5baa140 |
15 | 10253a7e03560 |
hex | 773c68fc58ac |
131101343111340 has 240 divisors, whose sum is σ = 470113699233024. Its totient is φ = 29960212867200.
The previous prime is 131101343111339. The next prime is 131101343111351. The reversal of 131101343111340 is 43111343101131.
131101343111340 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 0 + 1 + 3 + 4 + 311 + 1 + 340 = 666.
It is a super-3 number, since 3×1311013431113403 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 57521275 + ... + 59757005.
Almost surely, 2131101343111340 is an apocalyptic number.
131101343111340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131101343111340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (235056849616512).
131101343111340 is an abundant number, since it is smaller than the sum of its proper divisors (339012356121684).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131101343111340 is a wasteful number, since it uses less digits than its factorization.
131101343111340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2240930 (or 2240919 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 27.
Adding to 131101343111340 its reverse (43111343101131), we get a palindrome (174212686212471).
The spelling of 131101343111340 in words is "one hundred thirty-one trillion, one hundred one billion, three hundred forty-three million, one hundred eleven thousand, three hundred forty".
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