Base | Representation |
---|---|
bin | 11101110011110001101001… |
… | …000110111000000110101011 |
3 | 122012012011111011012221010202 |
4 | 131303301221012320012223 |
5 | 114140431023324402301 |
6 | 1142455043154502415 |
7 | 36420521356100261 |
oct | 3563615106700653 |
9 | 565164434187122 |
10 | 131101345153451 |
11 | 3885584a596992 |
12 | 1285439b294a0b |
13 | 581ca5ac4783a |
14 | 24534a617c431 |
15 | 10253a81a866b |
hex | 773c691b81ab |
131101345153451 has 2 divisors, whose sum is σ = 131101345153452. Its totient is φ = 131101345153450.
The previous prime is 131101345153447. The next prime is 131101345153531. The reversal of 131101345153451 is 154351543101131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131101345153451 - 22 = 131101345153447 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (131101345153151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550672576725 + 65550672576726.
It is an arithmetic number, because the mean of its divisors is an integer number (65550672576726).
Almost surely, 2131101345153451 is an apocalyptic number.
131101345153451 is a deficient number, since it is larger than the sum of its proper divisors (1).
131101345153451 is an equidigital number, since it uses as much as digits as its factorization.
131101345153451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 38.
Adding to 131101345153451 its reverse (154351543101131), we get a palindrome (285452888254582).
The spelling of 131101345153451 in words is "one hundred thirty-one trillion, one hundred one billion, three hundred forty-five million, one hundred fifty-three thousand, four hundred fifty-one".
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