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1311020034 = 234313733701
BaseRepresentation
bin100111000100100…
…1001010000000010
310101100220201101120
41032021021100002
510141110120114
6334031413110
744326325562
oct11611112002
93340821346
101311020034
11613044835
12307084196
1317b7c5bcc
14c618cda2
157a16a5a9
hex4e249402

1311020034 has 32 divisors (see below), whose sum is σ = 2685697344. Its totient is φ = 426417600.

The previous prime is 1311020017. The next prime is 1311020047. The reversal of 1311020034 is 4300201131.

1311020034 = 312 + 322 + ... + 15782.

It is a super-2 number, since 2×13110200342 = 3437547059098722312, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311019995 and 1311020022.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 352384 + ... + 356084.

It is an arithmetic number, because the mean of its divisors is an integer number (83928042).

Almost surely, 21311020034 is an apocalyptic number.

1311020034 is an abundant number, since it is smaller than the sum of its proper divisors (1374677310).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311020034 is a wasteful number, since it uses less digits than its factorization.

1311020034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5122.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 1311020034 is about 36208.0106330077. The cubic root of 1311020034 is about 1094.4681038843.

Adding to 1311020034 its reverse (4300201131), we get a palindrome (5611221165).

The spelling of 1311020034 in words is "one billion, three hundred eleven million, twenty thousand, thirty-four".

Divisors: 1 2 3 6 43 86 129 258 1373 2746 3701 4119 7402 8238 11103 22206 59039 118078 159143 177117 318286 354234 477429 954858 5081473 10162946 15244419 30488838 218503339 437006678 655510017 1311020034