1311023410201 has 4 divisors (see below), whose sum is σ = 1317236791504. Its totient is φ = 1304810028900.

The previous prime is 1311023410199. The next prime is 1311023410237. The reversal of 1311023410201 is 1020143201131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311023410201 - 2¹ = 1311023410199 is a prime.

It is a super-4 number, since 4×1311023410201⁴ (a number of 50 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311023410271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3106690335 + ... + 3106690756.

It is an arithmetic number, because the mean of its divisors is an integer number (329309197876).

Almost surely, 2^{1311023410201} is an apocalyptic number.

It is an amenable number.

1311023410201 is a deficient number, since it is larger than the sum of its proper divisors (6213381303).

1311023410201 is an equidigital number, since it uses as much as digits as its factorization.

1311023410201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6213381302.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1311023410201 its reverse (1020143201131), we get a palindrome (2331166611332).

The spelling of 1311023410201 in words is "one trillion, three hundred eleven billion, twenty-three million, four hundred ten thousand, two hundred one".