131102454550433 has 4 divisors (see below), whose sum is σ = 131109975791808. Its totient is φ = 131094933309060.

The previous prime is 131102454550423. The next prime is 131102454550471. The reversal of 131102454550433 is 334055454201131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131102454550433 is a prime.

It is a super-3 number, since 3×131102454550433³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131102454550423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3760594541 + ... + 3760629402.

It is an arithmetic number, because the mean of its divisors is an integer number (32777493947952).

Almost surely, 2^{131102454550433} is an apocalyptic number.

It is an amenable number.

131102454550433 is a deficient number, since it is larger than the sum of its proper divisors (7521241375).

131102454550433 is an equidigital number, since it uses as much as digits as its factorization.

131102454550433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7521241374.

The product of its (nonzero) digits is 432000, while the sum is 41.

The spelling of 131102454550433 in words is "one hundred thirty-one trillion, one hundred two billion, four hundred fifty-four million, five hundred fifty thousand, four hundred thirty-three".