Base | Representation |
---|---|
bin | 11101110011110011010000… |
… | …011110101011010100001011 |
3 | 122012012022222000121002221122 |
4 | 131303303100132223110023 |
5 | 114140443101314231041 |
6 | 1142455531230425455 |
7 | 36420612345246146 |
oct | 3563632036532413 |
9 | 565168860532848 |
10 | 131103079445771 |
11 | 3885655a551424 |
12 | 128547a406228b |
13 | 581cc7633ca04 |
14 | 24535cc62d05d |
15 | 102545a582c4b |
hex | 773cd07ab50b |
131103079445771 has 2 divisors, whose sum is σ = 131103079445772. Its totient is φ = 131103079445770.
The previous prime is 131103079445743. The next prime is 131103079445777. The reversal of 131103079445771 is 177544970301131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131103079445771 - 246 = 60734335268107 is a prime.
It is a super-3 number, since 3×1311030794457713 (a number of 43 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (131103079445777) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551539722885 + 65551539722886.
It is an arithmetic number, because the mean of its divisors is an integer number (65551539722886).
Almost surely, 2131103079445771 is an apocalyptic number.
131103079445771 is a deficient number, since it is larger than the sum of its proper divisors (1).
131103079445771 is an equidigital number, since it uses as much as digits as its factorization.
131103079445771 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2222640, while the sum is 53.
The spelling of 131103079445771 in words is "one hundred thirty-one trillion, one hundred three billion, seventy-nine million, four hundred forty-five thousand, seven hundred seventy-one".
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